LeetCode 108. Convert Sorted Array to Binary Search Tree Posted on 2017-06-01 | In LeetCode | Question Given an array where elements are sorted in ascending order, convert it to a height balanced BST. Explanation 递归,每次找到根节点就行。 Code 12345678910111213141516171819202122232425262728/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */public class Solution { public TreeNode sortedArrayToBST(int[] nums) { if (nums == null || nums.length == 0) return null; return helper(nums, 0, nums.length-1); } public TreeNode helper(int[] nums, int start, int end) { if (nums == null) return null; //base case if (start > end) return null; int mid = start + (end - start)/2; TreeNode root = new TreeNode(nums[mid]); root.left = helper(nums, start, mid-1); root.right = helper(nums, mid+1, end); return root; }}